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Cease reinventing the wheel
local data = mw.loadData( 'Module:Ancient Olympiads/data' )
local lang = mw.language.getContentLanguage()
local length = require( 'Module:Array length')
local p = {}
function p._main( inputYear )
-- Convert the input to an integer if possible. Return "N/A" if the input could
-- not be converted, or if the converted input is too big or too small.
inputYear = tonumber( inputYear )
if not inputYear or inputYear > tonumber( lang:formatDate( 'Y' ) ) then
return "''N/A''"
end
local dataLength = length(data)
-- Find the year in the data page and display the output.
for i = dataLength, 1, -1 do
local t = data[i]
if inputYear - 1 == t.year then
-- year of the Olympiad, test with = p._main( -495 )
-- The input year in the calendar is one after the expected (-775 for the year 776 BC). This is why all values need to be corrected by 1.
-- Year of Olympiad creates autolink to same page, therefore eliminated here
return string.format(
'%s [[Olympiad]] ([[%s|victor]][[Winner of the Stadion race|)¹]]',
t.numberOl, t.winner
)
end
if inputYear > t.year then
-- Years 2-4 of the Olympiad, test with = p._main( -494 ) etc.
-- It would be nice, if the string could be as follows:
-- '[[%s]] [[Olympiad]], [[%d BC|year %d]]',
-- t.numberOl, inputYear * - 1 + 1, inputYear - t.year
-- but unfortunately it links to the very same page and won't be displayed as a link but in bold.
return string.format(
'[[%s|%s]] [[Olympiad]], year %d',
t.yearBC, t.numberOl, inputYear - t.year
)
end
end
-- If input year is before 776 BC (-775), the year of the first Olympiad.
return string.format(
'%d before [[776 BC|1st]] [[Olympiad]]',
inputYear * -1 - 775
)
end
function p.main( frame )
local args = require( 'Module:Arguments' ).getArgs( frame, {
parentOnly = true
} )
return p._main( args[ 1 ] )
end
return p
local lang = mw.language.getContentLanguage()
local length = require( 'Module:Array length')
local p = {}
function p._main( inputYear )
-- Convert the input to an integer if possible. Return "N/A" if the input could
-- not be converted, or if the converted input is too big or too small.
inputYear = tonumber( inputYear )
if not inputYear or inputYear > tonumber( lang:formatDate( 'Y' ) ) then
return "''N/A''"
end
local dataLength = length(data)
-- Find the year in the data page and display the output.
for i = dataLength, 1, -1 do
local t = data[i]
if inputYear - 1 == t.year then
-- year of the Olympiad, test with = p._main( -495 )
-- The input year in the calendar is one after the expected (-775 for the year 776 BC). This is why all values need to be corrected by 1.
-- Year of Olympiad creates autolink to same page, therefore eliminated here
return string.format(
'%s [[Olympiad]] ([[%s|victor]][[Winner of the Stadion race|)¹]]',
t.numberOl, t.winner
)
end
if inputYear > t.year then
-- Years 2-4 of the Olympiad, test with = p._main( -494 ) etc.
-- It would be nice, if the string could be as follows:
-- '[[%s]] [[Olympiad]], [[%d BC|year %d]]',
-- t.numberOl, inputYear * - 1 + 1, inputYear - t.year
-- but unfortunately it links to the very same page and won't be displayed as a link but in bold.
return string.format(
'[[%s|%s]] [[Olympiad]], year %d',
t.yearBC, t.numberOl, inputYear - t.year
)
end
end
-- If input year is before 776 BC (-775), the year of the first Olympiad.
return string.format(
'%d before [[776 BC|1st]] [[Olympiad]]',
inputYear * -1 - 775
)
end
function p.main( frame )
local args = require( 'Module:Arguments' ).getArgs( frame, {
parentOnly = true
} )
return p._main( args[ 1 ] )
end
return p
